`Mn(NO_(3))_(2)+2NaOH to Mn(OH)_(2)darr+2NaNO_(3)`

Options

A. For precipitate formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction for the equation given:

**Step 1: Write down the chemical equation.**
The reaction is:
\[ \text{Mn(NO}_3\text{)}_2 + 2 \text{NaOH} \rightarrow \text{Mn(OH)}_2 + 2 \text{NaNO}_3 \]

**Step 2: Identify the reactants and products.**
- Reactants: Manganese(II) nitrate \((\text{Mn(NO}_3\text{)}_2)\) and Sodium hydroxide \((\text{NaOH})\)
- Products: Manganese(II) hydroxide \((\text{Mn(OH)}_2)\) and Sodium nitrate \((\text{NaNO}_3)\)

**Step 3: Analyze the state of the reactants and products.**
Both reactants, \(\text{Mn(NO}_3\text{)}_2\) and \(\text{NaOH}\), are in aqueous solution, meaning they are dissolved in water. The product \(\text{Mn(OH)}_2\) is indicated to be a precipitate, as suggested by the downward arrow in the equation.

**Step 4: Determine the type of reaction.**
Since a precipitate (\(\text{Mn(OH)}_2\)) is formed from the reaction of two aqueous solutions, this indicates that the reaction is a **precipitate formation reaction**.

**Step 5: Conclude the type of reaction.**
The answer is that this reaction is a **precipitate formation reaction**.

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