`SrC_(2)O_(4)darr+2HCl to SrCl_(2)+H_(2)C_(2)O_(4)`

Options

A. For precipitate formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction represented by the equation:

\[ \text{SrC}_2\text{O}_4 + 2 \text{HCl} \rightarrow \text{SrCl}_2 + \text{H}_2\text{C}_2\text{O}_4 \]

we will analyze the components involved in the reaction step by step.

### Step 1: Identify the Reactants and Products
- **Reactants**: Strontium oxalate (\( \text{SrC}_2\text{O}_4 \)) and hydrochloric acid (\( \text{HCl} \)).
- **Products**: Strontium chloride (\( \text{SrCl}_2 \)) and oxalic acid (\( \text{H}_2\text{C}_2\text{O}_4 \)).

### Step 2: Analyze the State of Reactants
- The presence of a downward arrow (↓) next to \( \text{SrC}_2\text{O}_4 \) indicates that it is a precipitate. This means that \( \text{SrC}_2\text{O}_4 \) is not soluble in the reaction medium and forms a solid.

### Step 3: Analyze the State of Products
- In the product side, there is no downward arrow next to \( \text{SrCl}_2 \) or \( \text{H}_2\text{C}_2\text{O}_4 \). This indicates that neither of these products is a precipitate.

### Step 4: Determine the Type of Reaction
- Since the precipitate \( \text{SrC}_2\text{O}_4 \) is present in the reactants and is not formed in the products, it indicates that the precipitate has dissolved during the reaction.

### Conclusion
- Therefore, the reaction can be classified as a **precipitate dissolution reaction**.

### Final Answer
The type of reaction is a **precipitate dissolution reaction**.

---