`K_(4)[Fe(CN)_(6)]+2CuSO_(4)toCu_(2)[Fe(CN)_(6)]darr+2K_(2) SO_(4)`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction for the given equation \( K_4[Fe(CN)_6] + 2CuSO_4 \rightarrow Cu_2[Fe(CN)_6] + 2K_2SO_4 \), we will analyze the reactants and products step by step.

### Step 1: Identify the Reactants
The reactants in the equation are:
- \( K_4[Fe(CN)_6] \) (Potassium ferrocyanide)
- \( 2CuSO_4 \) (Copper(II) sulfate)

Both of these compounds are soluble in water.

### Step 2: Identify the Products
The products of the reaction are:
- \( Cu_2[Fe(CN)_6] \) (Copper(II) ferrocyanide)
- \( 2K_2SO_4 \) (Potassium sulfate)

### Step 3: Analyze Solubility of Products
In the product side:
- \( Cu_2[Fe(CN)_6] \) is known to be insoluble in water and will precipitate out of the solution.
- \( K_2SO_4 \) is soluble in water.

### Step 4: Determine the Type of Reaction
Since a precipitate (\( Cu_2[Fe(CN)_6] \)) is formed from the reaction of two soluble reactants, this indicates that the reaction is a **precipitate formation reaction**.

### Conclusion
The type of reaction is a **precipitate formation reaction**.