`MCrO_(4)darr(M^(2+)=Ba^(2+)Pb^(2+))+AcOHto`No dissolution

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the question regarding the reaction of MCrO₄ with AcOH, we will analyze the components involved and determine the nature of the reaction step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in the equation are MCrO₄ and AcOH. Here, M represents either Ba²⁺ or Pb²⁺.

2. **Understand the Nature of MCrO₄**:
- MCrO₄ is a chromate salt. The chromate ion (CrO₄²⁻) can form precipitates with certain metal ions. In this case, we are considering Ba²⁺ and Pb²⁺ ions.

3. **Analyze the Reaction with AcOH**:
- AcOH (acetic acid) is a weak acid. When it is mixed with MCrO₄, we need to consider whether it can dissolve the chromate precipitate or not.

4. **Evaluate the Solubility**:
- The problem states that there is "no dissolution." This implies that the precipitate formed by MCrO₄ does not dissolve in AcOH. Therefore, no new products are formed in this reaction.

5. **Determine the Type of Reaction**:
- Since there is no dissolution and no new products are formed, this indicates that there is no reaction occurring. Thus, the correct classification for this reaction is "no reaction."

6. **Conclusion**:
- Based on the analysis, the answer to the question is that the reaction is classified as "no reaction."

### Final Answer:
The reaction of MCrO₄ with AcOH results in "no reaction."

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