`BaCO_(3)darr+CO_(2)+H_(2)O to Ba(HCO_(3))_(2)`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction represented by the equation \( \text{BaCO}_3 \, \rightleftharpoons \, \text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{Ba(HCO}_3)_2 \), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Products:**
- The reactants are barium carbonate (\( \text{BaCO}_3 \)), carbon dioxide (\( \text{CO}_2 \)), and water (\( \text{H}_2\text{O} \)).
- The product is barium hydrogen carbonate (\( \text{Ba(HCO}_3)_2 \)).

2. **Analyze the State of Reactants:**
- Barium carbonate (\( \text{BaCO}_3 \)) is a solid and is indicated as a precipitate in the reaction. The downward arrow suggests that it is not soluble in water.

3. **Analyze the State of Products:**
- Barium hydrogen carbonate (\( \text{Ba(HCO}_3)_2 \)) is soluble in water. This means that it will not precipitate out of solution.

4. **Determine the Type of Reaction:**
- Since we start with a solid precipitate (\( \text{BaCO}_3 \)) that dissolves to form a soluble compound (\( \text{Ba(HCO}_3)_2 \)), this indicates that the reaction involves the dissolution of a precipitate.

5. **Conclusion:**
- The reaction can be classified as a **precipitate dissolution reaction** because a solid precipitate is converted into a soluble compound.

### Final Answer:
The type of reaction is a **precipitate dissolution reaction**.