`Na_(2)S_(2)O_(3)+BaCl_(2) to BaS_(2)O_(3)darr+2NaCl`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the given reaction of sodium thiosulfate (Na₂S₂O₃) with barium chloride (BaCl₂), we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Sodium thiosulfate (Na₂S₂O₃)
- Barium chloride (BaCl₂)

### Step 2: Write the Chemical Equation
The chemical equation for the reaction is:
\[ \text{Na}_2\text{S}_2\text{O}_3 + \text{BaCl}_2 \rightarrow \text{BaS}_2\text{O}_3 + 2\text{NaCl} \]

### Step 3: Identify the Products
The products of the reaction are:
- Barium thiosulfate (BaS₂O₃), which is a precipitate
- Sodium chloride (NaCl)

### Step 4: Determine the Type of Reaction
This reaction can be classified as a **precipitation reaction** because a solid (precipitate) is formed when two aqueous solutions are mixed. In this case, barium thiosulfate (BaS₂O₃) is the precipitate that forms.

### Step 5: Conclusion
Based on the analysis, the correct classification of the reaction is that it is a **precipitate formation reaction**.

### Final Answer
The reaction is classified as a **precipitate formation reaction**.

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