`Ba(AcO)_(2)+K_(2)CrO_(4) to BaCrO_(4)darr+2AcOK`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the given reaction \( \text{Ba(AcO)}_2 + \text{K}_2\text{CrO}_4 \rightarrow \text{BaCrO}_4 \downarrow + 2 \text{AcOK} \), we will analyze the type of reaction taking place.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are barium acetate \( \text{Ba(AcO)}_2 \) and potassium chromate \( \text{K}_2\text{CrO}_4 \).
- The products are barium chromate \( \text{BaCrO}_4 \) and potassium acetate \( \text{AcOK} \).

2. **Determine the Physical States**:
- Barium acetate and potassium chromate are soluble in water, while barium chromate is insoluble and precipitates out of the solution. The down arrow (↓) indicates that \( \text{BaCrO}_4 \) is a precipitate.

3. **Classify the Reaction**:
- Since there is no precipitate on the reactant side and a precipitate (barium chromate) is formed on the product side, this reaction is classified as a **precipitate formation reaction**.

4. **Conclusion**:
- The correct classification of the reaction \( \text{Ba(AcO)}_2 + \text{K}_2\text{CrO}_4 \rightarrow \text{BaCrO}_4 \downarrow + 2 \text{AcOK} \) is that it is a **precipitate formation reaction**.

### Final Answer:
The reaction is classified as a **precipitate formation reaction**.