`Sr(ACO)_(2)+Ag_(2)SO_(4) to 2AcOAgdarr+SrSO_(4)darr`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To determine the type of reaction represented by the equation:

\[ \text{Sr(AcO)}_2 + \text{Ag}_2\text{SO}_4 \rightarrow 2 \text{AcOAg} \downarrow + \text{SrSO}_4 \downarrow \]

we can analyze the components and the changes that occur during the reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are strontium acetate \(\text{Sr(AcO)}_2\) and silver sulfate \(\text{Ag}_2\text{SO}_4\).
- The products are silver acetate \(\text{AcOAg}\) and strontium sulfate \(\text{SrSO}_4\).

2. **Check for Precipitate Formation**:
- In this reaction, both products, silver acetate (\(2 \text{AcOAg}\)) and strontium sulfate (\(\text{SrSO}_4\)), are indicated to form precipitates (denoted by the downward arrows).
- This suggests that both products are insoluble in the reaction medium.

3. **Determine the Type of Reaction**:
- Since two new products are formed and both are precipitates, this indicates that a double displacement reaction (also known as a metathesis reaction) has occurred.
- In this case, the silver ions (\(\text{Ag}^+\)) from silver sulfate exchange with the acetate ions (\(\text{AcO}^-\)) from strontium acetate, leading to the formation of silver acetate and strontium sulfate.

4. **Conclusion**:
- The reaction can be classified as a **precipitate formation reaction**, as it results in the formation of two solid precipitates from the reactants.

### Final Answer:
The reaction is a **precipitate formation reaction**.

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