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Ca(OH)(2)+CO(2)toCaCO(3)darr+2H(2)O...

`Ca(OH)_(2)+CO_(2)toCaCO_(3)darr+2H_(2)O`

A

For precipitate formation formation reaction

B

For precipitate dissolution reaction

C

For precipitate exchange reaction

D

For no reaction

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The correct Answer is:
To analyze the given reaction \( \text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + 2\text{H}_2\text{O} \) and determine the type of reaction it represents, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants and Products**: - The reactants are calcium hydroxide (\( \text{Ca(OH)}_2 \)) and carbon dioxide (\( \text{CO}_2 \)). - The products are calcium carbonate (\( \text{CaCO}_3 \)) and water (\( \text{H}_2\text{O} \)). 2. **Determine the Nature of the Reaction**: - In this reaction, calcium hydroxide reacts with carbon dioxide to form calcium carbonate and water. - Calcium carbonate (\( \text{CaCO}_3 \)) is a solid that precipitates out of the solution. 3. **Classify the Reaction**: - Since a solid (precipitate) is formed from the reaction of two aqueous solutions, this indicates that the reaction is a **precipitate formation reaction**. - The formation of a solid from the reactants is a key characteristic of this type of reaction. 4. **Conclusion**: - Therefore, the correct classification of the reaction \( \text{Ca(OH)}_2 + \text{CO}_2 \rightarrow \text{CaCO}_3 + 2\text{H}_2\text{O} \) is a **precipitate formation reaction**. ### Final Answer: The reaction is classified as a **precipitate formation reaction**. ---
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Ca(OH)_(2)+SO_(2) to CaSO_(3)darr+H_(2)O

Ca(OH)_(2)+SO_(2) to CaSO_(3)darr+H_(2)O

Ba(OH)_(2)+CO_(2) to BaCO_(3) darr+H_(2)O

Ba(OH)_(2)+SO_(2) to BaSO_(3)darr+H_(2)O

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2)to2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+) to R_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-)toR_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. What is the mass of Ca(OH)_(2) required for 10 litre of water remove temporary hardness of 100 PPm due to Ca(HCO_(3))_(2) ?

A water is said to be soft water if it produces sufficient foam with the soap and waterthat does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2)to2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-)toR_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. A 200 g sample of hard water is passed through the column of cation exchange resin, in which H^(+) is exchanged by Ca^(2+) .The outlet water of column required 50mL of 0.1 M NaOH for complete neutralization.What is the hardness of Ca^(2+) ion in PPm?

A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?

Ca(OH)_(2)+2FH to CaF_(2)darr+2H_(2)O

Ca(OH)_(2)+2FH to CaF_(2)darr+2H_(2)O

Permanent hardness is due to CI^(ɵ) and SO_4^(2-) of Mg^(2+) and Ca^(2+) and is removed by adding Na_2CO_3 . {:(CaSO_(4)+Na_(2)CO_(3)toCaCO_(3)+Na_(2)SO_(4)),(CaCl_(2)+Na_(2)CO_(3)toCaCO_(3)+2NaCl):} Which of the following statements is // are correct?

VK JAISWAL ENGLISH-TYPES OF REACTIONS-SUBJECTIVE PROBLEMS
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