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Ca(OH)(2)+SO(2) to CaSO(3)darr+H(2)O...

`Ca(OH)_(2)+SO_(2) to CaSO_(3)darr+H_(2)O`

A

For precipitate formation formation reaction

B

For precipitate dissolution reaction

C

For precipitate exchange reaction

D

For no reaction

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The correct Answer is:
To solve the reaction \( \text{Ca(OH)}_2 + \text{SO}_2 \rightarrow \text{CaSO}_3 + \text{H}_2\text{O} \), we will analyze the components and the type of reaction taking place step by step. ### Step 1: Identify the Reactants The reactants in the equation are: - Calcium hydroxide (\( \text{Ca(OH)}_2 \)) - Sulfur dioxide (\( \text{SO}_2 \)) ### Step 2: Identify the Products The products of the reaction are: - Calcium sulfite (\( \text{CaSO}_3 \)) - Water (\( \text{H}_2\text{O} \)) ### Step 3: Determine the Type of Reaction This reaction involves the combination of calcium hydroxide and sulfur dioxide to form calcium sulfite and water. We need to determine if this is a precipitation reaction. 1. **Precipitate Formation**: A precipitate is formed when two soluble reactants combine to form an insoluble product. In this case, calcium sulfite (\( \text{CaSO}_3 \)) is typically insoluble in water, indicating that it will precipitate out of the solution. ### Step 4: Write the Balanced Reaction The balanced reaction is already provided: \[ \text{Ca(OH)}_2 + \text{SO}_2 \rightarrow \text{CaSO}_3 \downarrow + \text{H}_2\text{O} \] The downward arrow indicates that calcium sulfite is a precipitate. ### Step 5: Conclusion Since a precipitate is formed in this reaction, we can conclude that this is a **precipitate formation reaction**. ### Final Answer The correct classification for the reaction \( \text{Ca(OH)}_2 + \text{SO}_2 \rightarrow \text{CaSO}_3 + \text{H}_2\text{O} \) is **precipitate formation reaction**. ---
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A water is said to be soft water if it produces sufficient foam with the soap and water that does not produce foam with soap is known as hard water. Hardness has been classified into two types (i)Temporary hardness (ii) Permanent hardness. Temporary hardness is due to presence of calcium and magnesium bicarbonate. It is simply removed by boiling as Ca(HCO_(3))_(2)overset(Delta)rarr CaCO_(3)darr+CO_(2)uarr+H_(2)O Mg(HCO_(3))_(2)overset(Delta)rarr MgCO_(3)darr+CO_(2)uarr+H_(2)O temporary hardness can also be removed by addition of slaked lime, Ca(OH)_(2) Ca(HCO_(3))_(2)+Ca(OH)_(2) to 2CaCO_(3)darr+2H_(2)O permanent hardsness is due to presencce of sulphates and chlorides of Ca,Mg,etc. It is removed by washing soda as CaCl_(2)+Na_(2)CO_(3) to CaCO_(3)darr+2NaCl CaSO(4)+Na_(2)CO_(3)to CaCO_(3)darr+Na_(2)SO_(4) Permanent hardness also removed by ion exchange resin process as 2RH+Ca^(2+)toR_(2)Ca+2H^(+) 2ROH+SO_(4)^(2-) to R_(2)SO_(4)+2OH^(-) The degree of hardness of water is measured in terms of PPm of CaCO_(3) 100 PPm means 100 g of CaCO_(3) is present in 10^(6) g of H_(2)O . If any other water sample which contain 120 PPm of MgSO_(4) , hardness in terms of CaCO_(3) is equal to =100 PPm. One litre of a sample of hard water (d=1 g/mL) cotains 136 mg of CaSO_(4) and 190 mg of MgCl_(2) . What is the total hardness of water in terms of CaCO_(3) ?

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