`Na_(2)SO_(3)+BaCl_(2) to BaSO_(3) darr+2NaCl`

Options

A. For precipitate formation formation reaction
B. For precipitate dissolution reaction
C. For precipitate exchange reaction
D. For no reaction

Answer

To solve the given reaction \( \text{Na}_2\text{SO}_3 + \text{BaCl}_2 \rightarrow \text{BaSO}_3 \downarrow + 2\text{NaCl} \), we will analyze the reaction step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are sodium sulfite (\( \text{Na}_2\text{SO}_3 \)) and barium chloride (\( \text{BaCl}_2 \)).

### Step 2: Write the Products
When sodium sulfite reacts with barium chloride, the products formed are barium sulfite (\( \text{BaSO}_3 \)) and sodium chloride (\( \text{NaCl} \)). The reaction can be written as:
\[ \text{Na}_2\text{SO}_3 + \text{BaCl}_2 \rightarrow \text{BaSO}_3 + 2\text{NaCl} \]

### Step 3: Determine the Type of Reaction
In this reaction, a solid precipitate of barium sulfite (\( \text{BaSO}_3 \)) is formed. The formation of a solid product from two aqueous solutions indicates that this is a precipitation reaction.

### Step 4: Indicate the Precipitate
The downward arrow (\( \downarrow \)) next to \( \text{BaSO}_3 \) signifies that it is a precipitate. This indicates that barium sulfite is not soluble in water and will settle out of the solution.

### Step 5: Conclusion
Based on the analysis, the reaction is classified as a **precipitate formation reaction** because it results in the formation of an insoluble product (precipitate) from soluble reactants.

### Final Answer
The correct classification of the reaction \( \text{Na}_2\text{SO}_3 + \text{BaCl}_2 \rightarrow \text{BaSO}_3 \downarrow + 2\text{NaCl} \) is **precipitate formation reaction**.

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