`underline(B)_(2)O_(3)+H_(2)O to H_(3)BO_(3)+H_(2)O hArr H[B(OH)_(4)]+H^(+)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given reaction and determine the type of products formed, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are:
- \( \underline{B}_2O_3 \) (Boron trioxide)
- \( H_2O \) (Water)

### Step 2: Write the Reaction
The reaction can be written as:
\[ \underline{B}_2O_3 + H_2O \rightarrow H_3BO_3 + H_2O \]

### Step 3: Identify the Products
The primary product of the reaction is:
- \( H_3BO_3 \) (Boric acid)

### Step 4: Determine the Oxidation State of Boron in \( H_3BO_3 \)
To find the oxidation state of boron in \( H_3BO_3 \):
- Let the oxidation state of boron be \( x \).
- The oxidation states of hydrogen and oxygen are +1 and -2 respectively.
- The equation can be set up as follows:
\[ x + 3(+1) + 3(-2) = 0 \]
\[ x + 3 - 6 = 0 \]
\[ x - 3 = 0 \]
\[ x = +3 \]

### Step 5: Classify the Product
Since the oxidation state of boron in \( H_3BO_3 \) is +3, and it contains hydrogen and oxygen, \( H_3BO_3 \) is classified as an oxyacid.

### Step 6: Determine the Suffix of the Oxyacid
In oxyacids, the suffix is determined by the oxidation state of the central atom:
- If the oxidation state is +3, the suffix is "ic".
- Therefore, \( H_3BO_3 \) is called boric acid.

### Step 7: Consider the Hydrolysis Reaction
The next part of the reaction involves:
\[ H_3BO_3 + H_2O \rightarrow H[B(OH)_4] + H^+ \]
This is a hydrolysis reaction, and since the oxidation state of boron remains +3, \( H[B(OH)_4] \) is also an oxyacid with the "ic" suffix.

### Final Conclusion
Both products, \( H_3BO_3 \) and \( H[B(OH)_4] \), are oxyacids with the "ic" suffix.

### Summary of the Solution
- The reaction produces oxyacids.
- The first product is \( H_3BO_3 \) (boric acid).
- The second product is \( H[B(OH)_4] \) (tetrahydroxyborate ion).
- Both products have the "ic" suffix.