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underline(S)O(3)+H(2)O to H(2)SO(4)...

`underline(S)O_(3)+H_(2)O to H_(2)SO_(4)`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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The correct Answer is:
a
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