`H_(4)underline(P_(2))O_(6)+H_(2)O to H_(3)PO_(3)+H_(3)PO_(4)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( H_4P_2O_6 + H_2O \rightarrow H_3PO_3 + H_3PO_4 \), we will analyze the reactants and products step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- \( H_4P_2O_6 \) (Dihydrogen diphosphate)
- \( H_2O \) (Water)

### Step 2: Identify the Products
The products of the reaction are:
- \( H_3PO_3 \) (Phosphorous acid)
- \( H_3PO_4 \) (Phosphoric acid)

### Step 3: Determine the Nature of the Products
Both \( H_3PO_3 \) and \( H_3PO_4 \) are oxyacids. An oxyacid is defined as an acid that contains hydrogen, oxygen, and another element (in this case, phosphorus).

### Step 4: Classify the Oxyacids
1. **For \( H_3PO_3 \)**:
- This acid contains phosphorus and has the formula \( H_3PO_3 \).
- The corresponding oxyanion is \( H_2PO_3^- \), which is called phosphite.
- Since the oxyanion ends with "ite", the acid is named using the suffix "ous", thus it is called phosphorous acid.

2. **For \( H_3PO_4 \)**:
- This acid contains phosphorus and has the formula \( H_3PO_4 \).
- The corresponding oxyanion is \( H_2PO_4^- \), which is called phosphate.
- Since the oxyanion ends with "ate", the acid is named using the suffix "ic", thus it is called phosphoric acid.

### Step 5: Conclusion
In the given reaction, we have two oxyacids:
- \( H_3PO_3 \) (phosphorous acid) with the suffix "ous".
- \( H_3PO_4 \) (phosphoric acid) with the suffix "ic".

Thus, the correct option is that the products are two oxyacids, one with the "ic" suffix and one with the "ous" suffix.

### Final Answer
The correct option is **C**: If the products are two oxyacids, one with "ic" and one with "ous".

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