`H_(4)underline(P_(2))O_(7)+H_(2)O to 2H_(3)PO_(4)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( H_4P_2O_7 + H_2O \rightarrow 2 H_3PO_4 \) step by step, we will analyze the reactants and products, identify the type of reaction, and determine the characteristics of the product.

### Step 1: Identify the Reactants
We have two reactants:
- \( H_4P_2O_7 \) (Pyrophosphoric acid)
- \( H_2O \) (Water)

### Step 2: Identify the Product
The product of the reaction is \( 2 H_3PO_4 \) (Phosphoric acid).

### Step 3: Understand the Reaction Type
This reaction can be classified as a hydrolysis reaction. Hydrolysis involves the reaction of a compound with water, leading to the formation of new products.

### Step 4: Analyze the Oxyacid Formation
The product \( H_3PO_4 \) is an oxyacid. Oxyacids are acids that contain hydrogen, oxygen, and another element (in this case, phosphorus).

### Step 5: Determine the Naming Convention
For oxyacids, the naming convention depends on the anion formed:
- If the anion ends in "ate," the acid name will end in "ic."
- If the anion ends in "ite," the acid name will end in "ous."

In our case, the anion derived from phosphoric acid is \( PO_4^{3-} \) (phosphate), which ends in "ate." Therefore, the corresponding acid is named phosphoric acid.

### Step 6: Conclusion
The reaction produces two molecules of phosphoric acid, which is an oxyacid with the "ic" suffix due to the presence of the phosphate ion.

### Final Answer
The correct option is that the product is an oxyacid with the "ic" suffix.

---