`underline(I)F_(5)+H_(2)O to HIO_(3)+HF`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To analyze the reaction \( IF_5 + H_2O \rightarrow HIO_3 + HF \), we will identify the nature of the products formed and classify them accordingly.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are \( IF_5 \) (iodine pentafluoride) and \( H_2O \) (water).
- The products are \( HIO_3 \) (iodic acid) and \( HF \) (hydrofluoric acid).

2. **Determine the Nature of the Products**:
- **For \( HIO_3 \)**:
- This compound contains hydrogen (H), oxygen (O), and iodine (I).
- It qualifies as an oxyacid because it has the structure of an acid containing hydrogen bonded to oxygen.
- The anion formed from this acid is \( IO_3^- \) (iodate).
- Since the anion ends in "ate," the corresponding acid is named using the suffix "ic," making it iodic acid.

- **For \( HF \)**:
- This compound contains hydrogen (H) and fluorine (F), but it does not contain oxygen.
- Therefore, \( HF \) is not classified as an oxyacid.

3. **Classify the Reaction**:
- In this reaction, we have one product that is an oxyacid (\( HIO_3 \)) and one product that is not an oxyacid (\( HF \)).
- The presence of \( HIO_3 \) indicates that the reaction produces an oxyacid with the "ic" suffix due to the iodate ion.

4. **Conclusion**:
- The correct classification of the products is that there is one oxyacid with the "ic" suffix and one compound that is not an oxyacid.
- Therefore, the correct option is that the product is an oxyacid with the "ic" suffix.