`underline(C)l_(2)O_(7)+H_(2)O to HClO_(4)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( \text{Cl}_2\text{O}_7 + \text{H}_2\text{O} \rightarrow \text{HClO}_4 \), we will analyze the components and identify the type of reaction taking place.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- \( \text{Cl}_2\text{O}_7 \) (Dichlorine heptoxide)
- \( \text{H}_2\text{O} \) (Water)

### Step 2: Identify the Product
The product of the reaction is:
- \( \text{HClO}_4 \) (Perchloric acid)

### Step 3: Determine the Type of Reaction
This reaction involves a non-metal oxide (dichlorine heptoxide) reacting with water to form an oxyacid (perchloric acid). This is a typical example of the formation of an oxyacid from a non-metal oxide and water.

### Step 4: Analyze the Oxyacid
An oxyacid is an acid that contains hydrogen, oxygen, and another element. In this case:
- The acid \( \text{HClO}_4 \) contains:
- Hydrogen (H)
- Oxygen (O)
- Chlorine (Cl)

### Step 5: Naming the Oxyacid
The naming convention for oxyacids is based on the anion formed. The anion corresponding to \( \text{HClO}_4 \) is \( \text{ClO}_4^- \), which is called "perchlorate." Since the anion ends with "ate," the acid is named using the suffix "ic," resulting in "perchloric acid."

### Conclusion
The reaction \( \text{Cl}_2\text{O}_7 + \text{H}_2\text{O} \rightarrow \text{HClO}_4 \) produces an oxyacid, specifically "perchloric acid." Therefore, the correct identification of the product is that it is an oxyacid with the "ic" suffix.

### Final Answer
The correct option is that the product is an oxyacid with the "ic" suffix.

---