`underline(S)iF_(4)+H_(2)O to H_(4)SiO_(4)+HF`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( \text{SiF}_4 + \text{H}_2\text{O} \rightarrow \text{H}_4\text{SiO}_4 + \text{HF} \), we will analyze the products formed and determine the type of acids involved.

### Step 1: Identify the reactants and products
- Reactants:
- \( \text{SiF}_4 \) (Silicon tetrafluoride)
- \( \text{H}_2\text{O} \) (Water)
- Products:
- \( \text{H}_4\text{SiO}_4 \) (Silicic acid)
- \( \text{HF} \) (Hydrofluoric acid)

### Step 2: Determine the nature of the products
- **Silicic acid (\( \text{H}_4\text{SiO}_4 \))**:
- This compound contains hydrogen, oxygen, and silicon.
- It fits the definition of an oxyacid, which is an acid that contains hydrogen, oxygen, and another element.
- When the bond between hydrogen and oxygen dissociates, it releases a proton (H⁺) and forms the anion \( \text{H}_3\text{SiO}_4^- \).

- **Hydrofluoric acid (\( \text{HF} \))**:
- This compound contains hydrogen and fluorine but does not contain oxygen.
- Therefore, it is not classified as an oxyacid.

### Step 3: Classify the oxyacid
- Since \( \text{H}_4\text{SiO}_4 \) is an oxyacid, we need to name it correctly.
- The anion derived from silicic acid is \( \text{SiO}_4^{4-} \), which is called silicate.
- The acid formed is silicic acid, and it follows the naming convention where the suffix "-ic" is used for acids derived from anions ending in "-ate".

### Step 4: Conclusion on the types of acids present
- In the reaction, we have:
- One oxyacid (\( \text{H}_4\text{SiO}_4 \)) with the "-ic" suffix.
- One non-oxyacid (\( \text{HF} \)).

Thus, the correct classification of the products is that we have one oxyacid with the "-ic" suffix.

### Final Answer
The correct option is: **If product is an oxyacid with IC suffix.**

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