`H_(2)underline(S)O_(5)+H_(2)O to H_(2)SO_(4)+H_(2)O_(2)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given chemical reaction, we will analyze the reactants and products step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in the reaction are \( H_2SO_5 \) (peroxymonosulfuric acid) and \( H_2O \) (water).

2. **Identify the Products**:
The products formed from the reaction are \( H_2SO_4 \) (sulfuric acid) and \( H_2O_2 \) (hydrogen peroxide).

3. **Determine the Type of Reaction**:
This reaction can be classified as a redox reaction where \( H_2SO_5 \) donates oxygen to water, leading to the formation of sulfuric acid and hydrogen peroxide.

4. **Check the Nature of the Products**:
- **For \( H_2SO_4 \)**:
- It is an oxyacid because it contains hydrogen, oxygen, and sulfur (another element).
- When dissociated, it releases protons (H⁺) and the sulfate ion (SO₄²⁻).
- **For \( H_2O_2 \)**:
- It contains only hydrogen and oxygen, and does not qualify as an oxyacid since it lacks another element.

5. **Conclude the Analysis**:
- Since one of the products is an oxyacid (sulfuric acid) and the other product (hydrogen peroxide) does not qualify as an oxyacid, we conclude that the reaction primarily results in the formation of an oxyacid.

6. **Select the Correct Option**:
- The correct option states that the product is an oxyacid with the IC suffix. Since \( H_2SO_4 \) is sulfuric acid (with the IC suffix), this option is correct.

### Final Answer:
The correct option for the reaction \( H_2SO_5 + H_2O \rightarrow H_2SO_4 + H_2O_2 \) is that the product is an oxyacid with the IC suffix.

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