`H_(4)underline(B_(2))O_(5)+H_(2)O to 2H_3BO_3`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given reaction \( H_4B_2O_5 + H_2O \rightarrow 2H_3BO_3 \) and determine the nature of the product, we can follow these steps:

### Step 1: Identify the Reactants and Products
We have the reactants \( H_4B_2O_5 \) (which is a boron compound) and \( H_2O \) (water). The product formed is \( 2H_3BO_3 \) (boric acid).

**Hint:** Look at the chemical formulas to identify the elements and their oxidation states.

### Step 2: Analyze the Product
The product \( H_3BO_3 \) is known as boric acid. It is important to recognize that boric acid is an oxyacid, which is an acid that contains oxygen.

**Hint:** Recall the definition of oxyacids; they contain hydrogen, oxygen, and another element (in this case, boron).

### Step 3: Determine the Oxidation State of Boron
In \( H_3BO_3 \), we can calculate the oxidation state of boron (B). The overall charge of the molecule is neutral, and we can set up the equation based on the known oxidation states of hydrogen (+1) and oxygen (-2).

Let the oxidation state of boron be \( x \):
\[ 3(+1) + x + 3(-2) = 0 \]
\[ 3 + x - 6 = 0 \implies x - 3 = 0 \implies x = +3 \]

**Hint:** Use the oxidation state rules to find the oxidation state of the central atom in the oxyacid.

### Step 4: Classify the Oxyacid
Since the oxidation state of boron in \( H_3BO_3 \) is +3, we classify it as boric acid. The naming convention indicates that acids with a higher oxidation state typically have the suffix "-ic".

**Hint:** Remember that acids derived from anions with a higher oxidation state typically end with "-ic".

### Step 5: Conclusion
Based on the analysis, we conclude that the product \( H_3BO_3 \) is indeed an oxyacid with the suffix "-ic". Therefore, the correct answer is that the product is an oxyacid with an "ic" suffix.

**Final Answer:** The product is an oxyacid with an "ic" suffix (Option A).