`H_(6)underline(Si_(2))O_(7)+H_(2)O to H_(4)SiO_(4)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the question regarding the reaction \( H_6Si_2O_7 + H_2O \rightarrow H_4SiO_4 \) and to determine the nature of the product formed, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are \( H_6Si_2O_7 \) (which is a silicate) and \( H_2O \) (water).
- The product formed is \( H_4SiO_4 \).

2. **Analyze the Product**:
- The product \( H_4SiO_4 \) contains silicon (Si), oxygen (O), and hydrogen (H).
- This indicates that it is likely an oxyacid since it contains oxygen and hydrogen bonded to a central atom (silicon).

3. **Determine the Oxidation State of Silicon**:
- To classify the oxyacid, we need to determine the oxidation state of silicon in \( H_4SiO_4 \).
- In \( H_4SiO_4 \), the oxidation state of silicon can be calculated as follows:
- Let the oxidation state of silicon be \( x \).
- The equation based on the compound's neutrality is:
\[ x + 4(-2) + 4(+1) = 0 \]
\[ x - 8 + 4 = 0 \implies x - 4 = 0 \implies x = +4 \]
- Thus, the oxidation state of silicon in \( H_4SiO_4 \) is +4.

4. **Classify the Oxyacid**:
- Oxyacids are typically named based on the oxidation state of the central atom.
- Since the oxidation state of silicon is +4, it corresponds to the suffix "ic" in naming.
- Therefore, the name of \( H_4SiO_4 \) is silicic acid.

5. **Conclusion**:
- Based on the analysis, \( H_4SiO_4 \) is an oxyacid with the suffix "ic".
- Thus, the correct answer to the question is option A: the product is an oxyacid with the suffix "ic".