`underline(P_(4))O_(10)+H_(2)O to H_(3)PO_(4)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the reaction \( P_4O_{10} + H_2O \rightarrow H_3PO_4 \) and determine the nature of the product formed, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
The reactants in this reaction are \( P_4O_{10} \) (tetraphosphorus decoxide) and \( H_2O \) (water).

2. **Determine the Product**:
The reaction between \( P_4O_{10} \) and \( H_2O \) produces \( H_3PO_4 \) (phosphoric acid).

3. **Classify the Product**:
Since \( H_3PO_4 \) contains hydrogen, oxygen, and phosphorus, it is classified as an oxyacid.

4. **Check for Oxidation States**:
To determine the correct suffix for the oxyacid, we need to find the oxidation state of phosphorus in \( H_3PO_4 \):
- In \( H_3PO_4 \), the oxidation state of phosphorus can be calculated as follows:
- Let the oxidation state of phosphorus be \( x \).
- The equation based on the overall charge of the compound is:
\[ 3(+1) + x + 4(-2) = 0 \]
\[ 3 + x - 8 = 0 \Rightarrow x = +5 \]

5. **Determine the Suffix**:
Since the oxidation state of phosphorus in \( H_3PO_4 \) is +5, we use the "ic" suffix for the name of the acid. Therefore, \( H_3PO_4 \) is named phosphoric acid.

6. **Final Conclusion**:
The product formed is an oxyacid with the "ic" suffix, specifically phosphoric acid.

### Final Answer:
The product formed is an oxyacid with the "ic" suffix (phosphoric acid).

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