`underline(P)OC l_(3)+H_(2)O to H_(3)PO_(4)+HCl`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given reaction \( \underline{P}OC l_{3} + H_{2}O \rightarrow H_{3}PO_{4} + HCl \), we will analyze the products formed and determine if they are oxyacids and their respective suffixes.

### Step-by-step Solution:

1. **Identify the Reactants**:
- The reactants are \( POCl_3 \) (phosphoryl chloride) and \( H_2O \) (water).

2. **Write the Reaction**:
- The reaction can be written as:
\[ POCl_3 + H_2O \rightarrow H_3PO_4 + HCl \]

3. **Identify the Products**:
- The products are \( H_3PO_4 \) (phosphoric acid) and \( HCl \) (hydrochloric acid).

4. **Determine the Nature of the Products**:
- **For \( H_3PO_4 \)**:
- This compound contains phosphorus, oxygen, and hydrogen. It is an oxyacid because it has oxygen in its structure.
- **For \( HCl \)**:
- This compound contains hydrogen and chlorine but no oxygen. Therefore, it is not an oxyacid.

5. **Check the Oxidation State of Phosphorus in \( H_3PO_4 \)**:
- In \( H_3PO_4 \), the oxidation state of phosphorus (P) can be calculated as follows:
- Each hydrogen contributes +1 (3 H = +3).
- Each oxygen contributes -2 (4 O = -8).
- Let the oxidation state of phosphorus be \( x \).
- The equation becomes:
\[ x + 3 - 8 = 0 \implies x = +5 \]
- Since the oxidation state of phosphorus is +5, which is a higher oxidation state, it indicates that the acid is named with the "ic" suffix.

6. **Conclusion**:
- The product \( H_3PO_4 \) is an oxyacid with the "ic" suffix (phosphoric acid).
- The product \( HCl \) is not an oxyacid.
- Therefore, there is only one oxyacid formed, which is \( H_3PO_4 \).

### Final Answer:
The answer is **A**: The product formed is an oxyacid with "ic" suffix.