`underline(B_(2))H_(6)+H_(2)O to H_(3)BO_(3)+H_(2)uarr`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the given question, we need to analyze the reaction between B2H6 (Diborane) and H2O (water) to determine the nature of the product formed, specifically whether it is an oxyacid and its suffix.

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in the reaction are B2H6 and H2O.
- B2H6 is known as diborane.
- H2O is water.

2. **Write the Reaction**: The reaction can be represented as:
\[ B_2H_6 + H_2O \rightarrow H_3BO_3 + H_2 \]
Here, H3BO3 is the product formed along with hydrogen gas (H2).

3. **Analyze the Product**: The product H3BO3 needs to be analyzed to determine if it is an oxyacid.
- H3BO3 contains boron (B), oxygen (O), and hydrogen (H).
- The presence of oxygen and hydrogen along with boron indicates that H3BO3 is indeed an oxyacid.

4. **Determine the Oxidation State of Boron**:
- In H3BO3, we need to find the oxidation state of boron (B).
- The overall charge of the molecule is neutral (0).
- Let the oxidation state of boron be \( x \).
- The equation can be set up as follows:
\[ 3(+1) + x + 3(-2) = 0 \]
\[ 3 + x - 6 = 0 \implies x - 3 = 0 \implies x = +3 \]
- Therefore, the oxidation state of boron in H3BO3 is +3.

5. **Identify the Suffix of the Oxyacid**:
- Since the oxidation state of boron in H3BO3 is +3, it indicates a higher oxidation state.
- Compounds with higher oxidation states typically have the suffix “-ic”.
- Thus, H3BO3 is named as boric acid (or ortho-boric acid), which has the “-ic” suffix.

6. **Conclusion**: Based on the analysis, we conclude that the product H3BO3 is an oxyacid with the “-ic” suffix.

### Final Answer:
The product formed is an oxyacid with the “-ic” suffix, specifically boric acid.

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