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underline(S)Ocl(2)+H(2)O to H(2)SO(3)+HC...

`underline(S)Ocl_(2)+H_(2)O to H_(2)SO_(3)+HCl`

A

If product is oxy acid with -ic suffix.

B

If product is oxy acid with -ous suffix

C

If product are two oxy acids one with -ic suffix and otherone with -ous suffix.

D

If product is not oxy acid, neither with -ic suffix nor with -ous suffix

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AI Generated Solution

The correct Answer is:
To solve the question regarding the reaction of SOCl₂ with H₂O to form H₂SO₃ and HCl, we will follow these steps: ### Step 1: Identify the Reactants and Products We start with the reactants: - SOCl₂ (thionyl chloride) - H₂O (water) The products of the reaction are: - H₂SO₃ (sulfurous acid) - HCl (hydrochloric acid) ### Step 2: Determine the Nature of the Products Next, we need to analyze the products: - H₂SO₃ contains sulfur (S), oxygen (O), and hydrogen (H), which indicates that it is an oxyacid. - HCl contains chlorine (Cl) and hydrogen (H) but does not contain oxygen, so it is not an oxyacid. ### Step 3: Classify the Oxyacid Now, we need to classify H₂SO₃: - The oxidation state of sulfur (S) in H₂SO₃ can be calculated. In H₂SO₃, the oxidation state of sulfur is +4. - Since the oxidation state of sulfur is +4, it is in a lower oxidation state compared to other oxyacids of sulfur, such as H₂SO₄ (sulfuric acid), which has sulfur in the +6 oxidation state. ### Step 4: Determine the Suffix Based on the oxidation state: - Oxyacids are named based on the oxidation state of the central atom (in this case, sulfur). - Since H₂SO₃ has sulfur in the +4 oxidation state, it is named "sulfurous acid," which uses the suffix "-ous." ### Step 5: Conclusion From our analysis, we conclude: - There is one oxyacid formed (H₂SO₃) and it has the suffix "-ous." - HCl is not an oxyacid. Thus, the correct answer is that the product is an oxyacid with a suffix. ### Final Answer The product is an oxyacid with a suffix (B). ---
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