`underline(Si)H_(4)+H_(2)O to H_(4)SiO_(4)+H_(2)`

Options

A. If product is oxy acid with -ic suffix.
B. If product is oxy acid with -ous suffix
C. If product are two oxy acids one with -ic suffix and otherone with -ous suffix.
D. If product is not oxy acid, neither with -ic suffix nor with -ous suffix

Answer

To solve the question regarding the reaction \( \underline{SiH_4} + H_2O \rightarrow H_4SiO_4 + H_2 \), we need to analyze the products formed and determine if they are oxyacids, and if so, whether they have the suffix "X" or "ic".

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are \( SiH_4 \) (silane) and \( H_2O \) (water).

2. **Write the Products**:
- The products of the reaction are \( H_4SiO_4 \) (which we need to analyze) and \( H_2 \) (hydrogen gas).

3. **Determine the Nature of the Product**:
- The product \( H_4SiO_4 \) contains silicon (Si), oxygen (O), and hydrogen (H). Since it contains oxygen and is derived from an acid (water), we can classify it as an oxyacid.

4. **Calculate the Oxidation State of Silicon**:
- In \( H_4SiO_4 \), we need to find the oxidation state of silicon (Si).
- Let the oxidation state of Si be \( x \). The equation can be set up as follows:
\[ 4 \text{(from H)} + x + 4 \text{(from O)} = 0 \]
This simplifies to:
\[ 4 + x - 8 = 0 \implies x = +4 \]
- Thus, the oxidation state of silicon in \( H_4SiO_4 \) is +4.

5. **Determine the Suffix of the Oxyacid**:
- Since silicon is in its highest oxidation state (+4), the oxyacid formed is named with the "X" suffix. Therefore, \( H_4SiO_4 \) is called silicic acid.

6. **Conclusion**:
- Based on the analysis, the product \( H_4SiO_4 \) is an oxyacid with the "X" suffix, specifically silicic acid.

### Final Answer:
The product is an oxyacid with "X" suffix, specifically silicic acid.