`Ca(OH)_(2)+Cl_(2) to CaOCl_(2) or Ca(OC l)Cl`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To solve the reaction \( \text{Ca(OH)}_2 + \text{Cl}_2 \rightarrow \text{Ca(OCl)}_2 \) or \( \text{Ca(OCl)Cl} \), we will analyze the oxidation states of the elements involved and determine the type of reaction taking place.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- The reactants are calcium hydroxide \( \text{Ca(OH)}_2 \) and chlorine gas \( \text{Cl}_2 \).
- The products can be either calcium oxychloride \( \text{Ca(OCl)}_2 \) or calcium dichloride \( \text{Ca(OCl)Cl} \).

2. **Assign Oxidation States**:
- In \( \text{Ca(OH)}_2 \):
- Calcium \( \text{Ca} \) has an oxidation state of +2.
- Oxygen \( \text{O} \) has an oxidation state of -2.
- Hydrogen \( \text{H} \) has an oxidation state of +1.
- In \( \text{Cl}_2 \):
- Chlorine \( \text{Cl} \) has an oxidation state of 0 (since it is in its elemental form).

3. **Determine the Oxidation States in the Product**:
- In \( \text{Ca(OCl)}_2 \):
- Calcium \( \text{Ca} \) remains +2.
- Oxygen \( \text{O} \) remains -2.
- The two chlorine atoms are in different oxidation states:
- One \( \text{Cl} \) is in the -1 oxidation state (outer Cl).
- Let’s denote the oxidation state of the inner \( \text{Cl} \) as \( x \).
- The equation for the oxidation states can be set up as:
\[ +2 + (-2) + x + (-1) = 0 \]
Simplifying gives:
\[ x - 1 = 0 \implies x = +1 \]
- Thus, one \( \text{Cl} \) is in the +1 oxidation state.

4. **Identify the Changes in Oxidation States**:
- Chlorine changes from 0 in \( \text{Cl}_2 \) to +1 in \( \text{Ca(OCl)}_2 \) (oxidation).
- Chlorine also changes from 0 in \( \text{Cl}_2 \) to -1 in \( \text{Ca(OCl)}_2 \) (reduction).

5. **Determine the Type of Reaction**:
- Since one species (chlorine) is both oxidized (to +1) and reduced (to -1), this is classified as a **disproportionation reaction**.

6. **Conclusion**:
- The correct product formed is \( \text{Ca(OCl)}_2 \) (bleaching powder), and the reaction is a disproportionation reaction.

### Final Answer:
The reaction \( \text{Ca(OH)}_2 + \text{Cl}_2 \) produces \( \text{Ca(OCl)}_2 \) (bleaching powder) and is classified as a disproportionation reaction.