`Ag+PCl_(5)overset(Delta)to AgCl+PCl_(3)`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To analyze the given chemical reaction \( \text{Ag} + \text{PCl}_5 \overset{\Delta}{\rightarrow} \text{AgCl} + \text{PCl}_3 \), we can break it down into steps to determine the type of reaction it represents.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- Reactants: Silver (Ag) and Phosphorus Pentachloride (PCl₅).
- Products: Silver Chloride (AgCl) and Phosphorus Trichloride (PCl₃).

2. **Determine the Nature of the Reaction**:
- In this reaction, silver (Ag) is replacing phosphorus in PCl₅.
- This indicates that one element (Ag) is displacing another element (P) from a compound (PCl₅).

3. **Classify the Reaction**:
- This type of reaction is known as a **displacement reaction** (also called a substitution reaction). In a displacement reaction, an ion in a compound is replaced by an atom or ion of another element.

4. **Confirm the Reaction Type**:
- Since Ag is in its elemental form and is displacing phosphorus from PCl₅ to form AgCl and PCl₃, we can confirm that this is indeed a displacement reaction.

5. **Conclusion**:
- Therefore, the correct classification for the reaction \( \text{Ag} + \text{PCl}_5 \overset{\Delta}{\rightarrow} \text{AgCl} + \text{PCl}_3 \) is a **displacement reaction**.