`NaI+H_(2)SO_(4)(Conc.) to Na_(2)SO_(4)+SO_(2)uarr+I_(2)uarr`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To analyze the reaction \( \text{NaI} + \text{H}_2\text{SO}_4 \) (conc.) → \( \text{Na}_2\text{SO}_4 + \text{SO}_2 + \text{I}_2 \) and determine the type of reaction, we can follow these steps:

### Step 1: Identify the oxidation states of the elements involved.
- In \( \text{NaI} \), the oxidation state of iodine (I) is -1.
- In \( \text{H}_2\text{SO}_4 \), the oxidation state of sulfur (S) is +6.
- In \( \text{Na}_2\text{SO}_4 \), the oxidation state of sulfur (S) remains +6.
- In \( \text{SO}_2 \), the oxidation state of sulfur (S) is +4.
- In \( \text{I}_2 \), the oxidation state of iodine (I) is 0.

### Step 2: Determine the changes in oxidation states.
- Iodine (I) is oxidized from -1 to 0 (loss of electrons).
- Sulfur (S) is reduced from +6 to +4 (gain of electrons).

### Step 3: Identify the type of reaction.
- Since oxidation and reduction are occurring simultaneously, this indicates a redox reaction.
- The reaction involves different compounds undergoing oxidation and reduction, which classifies it as an intermolecular redox reaction.

### Step 4: Eliminate other reaction types.
- The reaction does not involve thermal energy changes (no heat is applied), so it is not a thermal combination or thermal decomposition reaction.
- It is not a disproportionation reaction because disproportionation involves a single species undergoing both oxidation and reduction.
- It is also not a comproportionation reaction as that involves two different oxidation states of the same element combining to form a single product.

### Conclusion:
The type of reaction is an **intermolecular redox reaction**.

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