`3PbS+8HNO_(3)(Dil.) to 3Pb(NO_(3))_(2)+3S darr+2NO+4H_(2)O`

Options

A. For disproportionation reaction.
B. For comproportionation reaction.
C. For either intermolecular redox reaction or displacement reaction
D. For either thermal combination redox reaction or thermal decomposition redox reaction.

Answer

To determine the type of reaction for the given chemical equation:

**Given Reaction:**
\[ 3 \text{PbS} + 8 \text{HNO}_3 \text{(Dil.)} \rightarrow 3 \text{Pb(NO}_3)_2 + 3 \text{S} + 2 \text{NO} + 4 \text{H}_2\text{O} \]

### Step 1: Identify the Oxidation States
- **For PbS:**
- Lead (Pb) has an oxidation state of +2.
- Sulfur (S) has an oxidation state of -2.

- **For HNO3:**
- Hydrogen (H) has an oxidation state of +1.
- Nitrogen (N) has an oxidation state of +5.
- Oxygen (O) has an oxidation state of -2.

### Step 2: Calculate Oxidation States in Products
- **For Pb(NO3)2:**
- Lead (Pb) has an oxidation state of +2.
- Nitrogen (N) has an oxidation state of +5.

- **For Sulfur (S):**
- In elemental form, the oxidation state is 0.

- **For NO:**
- Nitrogen (N) has an oxidation state of +2.

- **For H2O:**
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.

### Step 3: Determine Changes in Oxidation States
- **Sulfur (S):**
- Changes from -2 in PbS to 0 in elemental sulfur (oxidation).

- **Nitrogen (N):**
- Changes from +5 in HNO3 to +2 in NO (reduction).

### Step 4: Identify the Type of Reaction
Since we have:
- Sulfur being oxidized (increase in oxidation state).
- Nitrogen being reduced (decrease in oxidation state).

This indicates that there is a simultaneous oxidation and reduction process occurring. Therefore, this reaction is classified as a **redox reaction**.

### Step 5: Determine if it is Intermolecular or Other Types
Since the oxidation and reduction involve different compounds (PbS and HNO3), this is classified as an **intermolecular redox reaction**.

### Conclusion
The reaction is an **intermolecular redox reaction**.

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