`NiCl_(2)+NH_(3)(excess)to [Ni(NH_(3))_(6)]^(2+)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between NiCl₂ and NH₃, we will follow these steps:

### Step 1: Identify the Reactants
The reactants in the reaction are Nickel(II) chloride (NiCl₂) and Ammonia (NH₃). We note that NH₃ is in excess.

**Hint:** Recognize the chemical formulas and their states in the reaction.

### Step 2: Write the Reaction
The reaction can be written as:
\[ \text{NiCl}_2 + \text{NH}_3 \text{ (excess)} \rightarrow [\text{Ni(NH}_3)_6]^{2+} \]

**Hint:** Understand that NH₃ acts as a ligand and forms a complex with Ni²⁺.

### Step 3: Determine the Type of Reaction
This reaction is a complexation reaction where ammonia (a ligand) coordinates with the nickel ion to form a complex ion.

**Hint:** Identify the type of reaction based on the formation of a complex.

### Step 4: Analyze the Product
The product formed is \([\text{Ni(NH}_3)_6]^{2+}\). This complex ion is known to be soluble in water.

**Hint:** Check the solubility of the product to determine if a precipitate forms.

### Step 5: Identify the Color of the Product
The complex \([\text{Ni(NH}_3)_6]^{2+}\) is known to be blue in color.

**Hint:** Remember the characteristic colors of transition metal complexes.

### Step 6: Conclusion
Since the product is a soluble complex and is colored (blue), the reaction will yield a colored solution rather than a precipitate.

**Final Answer:** The reaction will give a colored solution (specifically blue).

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