`Na_(2)[Zn(OH)_(4)]+4HCl to ZnCl_(2)+NaCl+H_(2)O`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To analyze the given reaction and determine the nature of the products, we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction provided is:
\[ \text{Na}_2[\text{Zn(OH)}_4] + 4 \text{HCl} \rightarrow \text{ZnCl}_2 + 2 \text{NaCl} + 4 \text{H}_2\text{O} \]

### Step 2: Identify the reactants and products
- **Reactants**: Sodium zincate \((\text{Na}_2[\text{Zn(OH)}_4])\) and hydrochloric acid \((\text{HCl})\).
- **Products**: Zinc chloride \((\text{ZnCl}_2)\), sodium chloride \((\text{NaCl})\), and water \((\text{H}_2\text{O})\).

### Step 3: Determine the solubility of the products
- **Zinc chloride (\(ZnCl_2\))**: Soluble in water.
- **Sodium chloride (\(NaCl\))**: Soluble in water.
- **Water (\(H_2O\))**: A solvent.

### Step 4: Analyze the physical state of the products
Since all the products are soluble in water, they will not form any precipitate. Therefore, we can conclude that the solution will remain clear.

### Step 5: Conclusion
Since all products are colorless and soluble, the final solution will be clear and colorless.

### Final Answer
The reaction will result in a clear and colorless solution.

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