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3KCN+Fe(CN)(3)darr to K(3)[Fe(CN)(6)]...

`3KCN+Fe(CN)_(3)darr to K_(3)[Fe(CN)_(6)]`

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To solve the given reaction \(3KCN + Fe(CN)_3 \rightarrow K_3[Fe(CN)_6]\) and determine the nature of the product, we can follow these steps: ### Step 1: Identify the reactants and products - The reactants are potassium cyanide (KCN) and iron(III) cyanide (Fe(CN)₃). - The product is potassium hexacyanoferrate(III), represented as \(K_3[Fe(CN)_6]\). ### Step 2: Analyze the reaction - In this reaction, three moles of KCN react with one mole of Fe(CN)₃ to form one mole of \(K_3[Fe(CN)_6]\). - This indicates that KCN is acting as a ligand that coordinates with the iron ion in Fe(CN)₃. ### Step 3: Determine the solubility of the product - The product \(K_3[Fe(CN)_6]\) is a complex ion that is soluble in water. - Since it is soluble, it will not form a precipitate. ### Step 4: Identify the oxidation state of iron in the product - In \(K_3[Fe(CN)_6]\), the iron is in the +3 oxidation state (Fe³⁺). - The oxidation state can be determined by considering the overall charge of the complex and the charge contributed by the cyanide ions (CN⁻). ### Step 5: Determine the color of the solution - The color of the solution is influenced by the oxidation state of iron. - Iron in the +3 oxidation state (Fe³⁺) typically imparts a yellow color to the solution. ### Conclusion - The reaction produces a colored solution, specifically a yellow solution, due to the presence of the Fe³⁺ ion in the complex. ### Final Answer - The reaction \(3KCN + Fe(CN)_3 \rightarrow K_3[Fe(CN)_6]\) results in a yellow colored solution. ---
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VK JAISWAL ENGLISH-TYPES OF REACTIONS-SUBJECTIVE PROBLEMS
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