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K(3)[Fe(CN)(6)]+FeCl(3) to Fe[Fe(CN)(6)]...

`K_(3)[Fe(CN)_(6)]+FeCl_(3) to Fe[Fe(CN)_(6)]darr`

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To solve the question regarding the reaction between \( K_3[Fe(CN)_6] \) and \( FeCl_3 \) to form \( Fe[Fe(CN)_6] \), we need to analyze the products formed and their characteristics. Here’s a step-by-step breakdown of the solution: ### Step 1: Identify the Reactants The reactants in the reaction are: - \( K_3[Fe(CN)_6] \) (Potassium hexacyanoferrate(II)) - \( FeCl_3 \) (Ferric chloride) ### Step 2: Determine the Reaction Type This reaction involves the formation of a complex. The \( K_3[Fe(CN)_6] \) acts as a ligand that coordinates with the iron ion from \( FeCl_3 \). ### Step 3: Write the Reaction The reaction can be written as: \[ K_3[Fe(CN)_6] + FeCl_3 \rightarrow Fe[Fe(CN)_6] + 3KCl \] ### Step 4: Analyze the Product The product formed is \( Fe[Fe(CN)_6] \), which is known as a complex ion. ### Step 5: Determine the Solubility of the Product The complex \( Fe[Fe(CN)_6] \) is soluble in water, meaning it will not precipitate out of solution. ### Step 6: Identify the Color of the Product The complex \( Fe[Fe(CN)_6] \) is known to have a brown color. Therefore, when it is formed in solution, it will impart a brown color to the solution. ### Step 7: Conclusion Since the product is a soluble complex and has a brown color, the answer to the question is that the solution will be colored (specifically brown). ### Final Answer The solution will be a colored solution (brown). ---
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In the Lassaigne’s test for nitrogen in an organic compound, the Prussian blue colour is obtained due to the formation of: (a) Na_(4)[Fe(CN)_(6)] (b) Fe_(4)[Fe(CN)_(6)]_(3) (c) Fe_(2)[Fe(CN)_(6)] (d) Fe_(3)[Fe(CN)_(6)]_(4)

A : K_(4)[Fe(CN)_(6)] and K_(3) [Fe(CN)_(6)] have different magnetic moment.. R: Magnetic moment is decided by the number of unpaired electron and both have different number of unpaired electrons.

A overset(KCN"added slowly")(to) underset(("Reddish brown precipitate"))(B) overset("In excess KCN precipitate dissolves")(to)underset(("Yellow solution"))(C) A overset(K_(4)Fe(CN)_(6))(to) underset(("Intense blue precipitate"))(D) overset(NaOH)(to) ("Red precipitate") A overset(Na_(2)HPO_(4))(to) underset(("Yellowish white precipitate"))(E) How many produces are correctly match? A=FeCl_(3), A=FeCl_(2), A=CuCl_(2), B=Fe(CN)_(3) B=K_(3)Fe(CN)_(6), C=K_(3)Fe(CN)_(6), C=K_(4)[Fe(CN)_(6)], D=Fe_(4)[Fe(CN)_(6)]_(3) D=Fe[Fe(CN)_(6)], E=FePO_(4)

For the reaction, 3Zn^(2+)+2K_(4)[Fe(CN)_(6)]rarr K_(2)Zn_(3)[Fe(CN)_(6)]_(2)+6K^(+) , what will be the equivalent weight of K_(4)[Fe(CN)_(6)] , if the molecular weight of K_(4)[Fe(CN)_(6)] is M ?

Which of the following is more stable ? (1) K_(4)[Fe(CN)_(6)] or K_(3)[Fe(CN)_(6)] (2) [Co(NH_(3))_(6)]^(3+) or [Co(en)_(2)(NH_(3))_(2)]^(3+) (3) [NiCl_(4)]^(2-) or [Ni(CN)_(4)]^(2-)

VK JAISWAL ENGLISH-TYPES OF REACTIONS-SUBJECTIVE PROBLEMS
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