`K_(3)[Fe(CN)_(6)]+FeCl_(2) to Fe_(3)[Fe(CN)_(6)]_(2)darr`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction \( K_3[Fe(CN)_6] + FeCl_2 \rightarrow Fe_3[Fe(CN)_6]_2 \), we will analyze the reactants and products step by step.

### Step 1: Identify the Reactants
The reactants in this reaction are:
- \( K_3[Fe(CN)_6] \) (Potassium hexacyanoferrate(II))
- \( FeCl_2 \) (Iron(II) chloride)

### Step 2: Understand the Reaction Type
This reaction is a double displacement reaction (also known as a metathesis reaction). In this type of reaction, the cations and anions exchange partners.

### Step 3: Predict the Products
When \( K_3[Fe(CN)_6] \) reacts with \( FeCl_2 \), the iron ions from \( FeCl_2 \) will combine with the hexacyanoferrate ions to form a complex. The expected product is \( Fe_3[Fe(CN)_6]_2 \), which is known as iron(III) hexacyanoferrate(II).

### Step 4: Analyze the Color of the Product
The product \( Fe_3[Fe(CN)_6]_2 \) is known to form a blue precipitate, commonly referred to as "Turnbull's Blue" or "Prussian Blue".

### Step 5: Conclusion
Based on the analysis, we can conclude the following about the reaction:
- The reaction produces a colored precipitate (blue).
- There is no formation of a colorless solution.
- The precipitate is not white; it is blue.

### Final Answer
The correct option for the question is that the reaction produces a colored precipitate, specifically a blue precipitate.

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