`KI+BiI_(2)darr to K[BiI_(4)]`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction \( \text{KI} + \text{BiI}_2 \rightarrow \text{K[BiI}_4] \), we will analyze the components of the reaction and the properties of the products formed.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are potassium iodide (KI) and bismuth(III) iodide (BiI₂).
- Note that BiI₂ is indicated as a precipitate, which means it is not soluble in the reaction medium.

2. **Understand the Reaction**:
- When KI is added to BiI₂, a complex ion is formed, which is \( \text{K[BiI}_4] \).
- This indicates that the iodide ions from KI are coordinating with the bismuth ion to form a complex.

3. **Determine the Solubility of the Products**:
- The complex \( \text{K[BiI}_4] \) is a soluble complex. This means that it will not precipitate out of the solution.
- Since it is soluble, we can conclude that no precipitate will form in this reaction.

4. **Identify the Color of the Complex**:
- The complex \( \text{K[BiI}_4] \) is known to have an orange color.
- This is an important detail as it indicates that the solution will have a distinct color due to the presence of the complex.

5. **Conclusion**:
- Since the reaction produces a soluble complex that is colored, we can conclude that the solution formed will be colored (specifically orange).
- Therefore, the options for the type of solution formed can be narrowed down to a colored solution.

### Final Answer:
The solution formed is a colored solution (orange).

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