`KI+AgNO_(3) to AgI darr`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between KI and AgNO₃, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in the given reaction are potassium iodide (KI) and silver nitrate (AgNO₃).

### Step 2: Write the Reaction
The reaction can be written as:
\[ \text{KI} + \text{AgNO}_3 \rightarrow \text{AgI} + \text{KNO}_3 \]
This indicates that potassium iodide reacts with silver nitrate to form silver iodide (AgI) and potassium nitrate (KNO₃).

### Step 3: Determine the Nature of the Product
In this reaction, AgI is formed. The notation "↓" indicates that AgI is a precipitate, meaning it is not soluble in the solution.

### Step 4: Identify the Color of the Precipitate
Silver iodide (AgI) is known to be a yellow precipitate. Therefore, when this reaction occurs, a yellow precipitate will form.

### Step 5: Eliminate Other Options
Since we are looking for the nature of the product:
- The options for the product could be colored or black precipitate, colored solution, clear or colorless solution, or white precipitate.
- We can eliminate the options of colored solution, clear solution, and white precipitate since AgI is a yellow precipitate.

### Conclusion
The correct answer is that the reaction produces a colored precipitate (specifically, a yellow precipitate).

### Final Answer
The reaction \( \text{KI} + \text{AgNO}_3 \) produces a yellow precipitate of AgI.

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