`Na_(2)CO_(3)+Pb(NO_(3))_(2) to PbCO_(3)darr+NaNO_(3)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between sodium carbonate (Na₂CO₃) and lead(II) nitrate [Pb(NO₃)₂], we need to analyze the products formed and their characteristics.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants are sodium carbonate (Na₂CO₃) and lead(II) nitrate [Pb(NO₃)₂].

2. **Write the Reaction**:
- The balanced chemical equation is:
\[ \text{Na}_2\text{CO}_3 + \text{Pb(NO}_3\text{)}_2 \rightarrow \text{PbCO}_3 \downarrow + 2\text{NaNO}_3 \]

3. **Analyze the Products**:
- The products of the reaction are lead(II) carbonate (PbCO₃) and sodium nitrate (NaNO₃).
- The downward arrow (↓) indicates that PbCO₃ is a precipitate.

4. **Determine the Nature of the Precipitate**:
- Lead(II) carbonate (PbCO₃) is known to be a white solid.

5. **Conclusion**:
- Since PbCO₃ is a white precipitate, the final answer to the question is that the reaction will form a **white precipitate**.

### Final Answer:
The reaction will form a **white precipitate**.

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