`Na_(2)CrO_(4)+HCl to H_(2)Cr_(2)O_(7)+Na_(2)SO_(4)`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the reaction given in the question, we need to analyze the reactants and products step by step.

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Sodium chromate (Na₂CrO₄)
- Hydrochloric acid (HCl)

### Step 2: Identify the Products
The products formed in the reaction are:
- Dichromic acid (H₂Cr₂O₇)
- Sodium sulfate (Na₂SO₄)

### Step 3: Determine the Nature of the Reaction
This reaction involves the combination of sodium chromate with hydrochloric acid. It is an acid-base reaction where the chromate ion (CrO₄²⁻) is converted into dichromate ion (Cr₂O₇²⁻) in the presence of an acid.

### Step 4: Check for Precipitation
In this reaction, we need to check if any precipitate is formed.
- There are no downward arrows in the reaction, indicating that no precipitate is formed on the reactant side.
- Similarly, there are no downward arrows on the product side, indicating that no precipitate is formed in the products either.

### Step 5: Analyze the Color of the Products
- The product H₂Cr₂O₇ (dichromic acid) is known to have a dark red color.
- Sodium sulfate (Na₂SO₄) is a colorless compound.

### Step 6: Conclusion
Since the product H₂Cr₂O₇ is dark red, the solution will be colored. Therefore, the answer to the question is that the solution formed is a colored solution.

### Final Answer
The correct option is **B: for colored solution**.

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