`(NH_(4))_(2)SO_(4)+Ba(OH)_(2) to BaSO_(4)darr+2NH_(3)uarr`

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Answer

To solve the given reaction `(NH₄)₂SO₄ + Ba(OH)₂ → BaSO₄ ↓ + 2NH₃ ↑`, we can break it down step by step.

### Step 1: Identify the Reactants
The reactants in the reaction are:
- Ammonium sulfate, \((NH₄)₂SO₄\)
- Barium hydroxide, \(Ba(OH)₂\)

### Step 2: Determine the Type of Reaction
This reaction is a **double displacement reaction** (also known as a metathesis reaction), where the cations and anions exchange partners. In this case, the ammonium ions (\(NH₄^+\)) and barium ions (\(Ba^{2+}\)) switch places.

### Step 3: Identify the Products
The products of the reaction are:
- Barium sulfate, \(BaSO₄\), which is a white precipitate.
- Ammonia gas, \(NH₃\), which is released as a gas.

### Step 4: Write the Balanced Equation
The balanced chemical equation for the reaction is:
\[ (NH₄)₂SO₄ + Ba(OH)₂ → BaSO₄ ↓ + 2NH₃ ↑ \]
This shows that one mole of ammonium sulfate reacts with one mole of barium hydroxide to produce one mole of barium sulfate and two moles of ammonia gas.

### Step 5: Identify the Observations
- **Precipitate Formation**: Barium sulfate forms as a white precipitate.
- **Gas Evolution**: Ammonia gas is released, which can be identified by its characteristic smell.

### Conclusion
The reaction is a double displacement reaction that results in the formation of a white precipitate of barium sulfate and the release of ammonia gas.

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