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Which of the following ionic/molecular s...

Which of the following ionic/molecular species does not disproportionate in water at room temperature?

A

`NO_(2)`

B

`Cu^(+)`

C

`MnO_(4)^(2-)`

D

`Ca(OCl)Cl`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given ionic/molecular species does not disproportionate in water at room temperature, we will analyze each species one by one. ### Step-by-Step Solution: 1. **Identify the Species**: The species given are: - NO2 (Nitrogen dioxide) - Cu⁺ (Copper(I) ion) - MnO4²⁻ (Manganate ion) - Ca(OCl)₂ (Calcium hypochlorite) 2. **Analyze NO2**: - When NO2 is dissolved in water, it forms HNO3 (Nitric acid) and HNO2 (Nitrous acid). - The oxidation states of nitrogen change from +4 in NO2 to +5 in HNO3 (oxidation) and +3 in HNO2 (reduction). - Since the same species (NO2) undergoes both oxidation and reduction, this is a disproportionation reaction. **Conclusion**: NO2 undergoes disproportionation. 3. **Analyze Cu⁺**: - When Cu⁺ is dissolved in water, it can disproportionate to form Cu (Copper) and Cu²⁺ (Copper(II) ion). - The oxidation states change from +1 in Cu⁺ to 0 in Cu (reduction) and +2 in Cu²⁺ (oxidation). - This indicates that Cu⁺ also undergoes disproportionation. **Conclusion**: Cu⁺ undergoes disproportionation. 4. **Analyze MnO4²⁻**: - When MnO4²⁻ is dissolved in water, it can disproportionate to form MnO4⁻ (Permanganate ion), MnO2 (Manganese dioxide), and OH⁻ (Hydroxide ion). - The oxidation states of manganese change from +6 in MnO4²⁻ to +7 in MnO4⁻ (oxidation) and +4 in MnO2 (reduction). - This indicates that MnO4²⁻ also undergoes disproportionation. **Conclusion**: MnO4²⁻ undergoes disproportionation. 5. **Analyze Ca(OCl)₂**: - When Ca(OCl)₂ is dissolved in water, it dissociates into Ca²⁺, Cl⁻, and OCl⁻ ions. - The oxidation states of chlorine in Cl⁻ and OCl⁻ remain the same (+1 for OCl⁻ and -1 for Cl⁻). - Since there is no change in oxidation states, this does not represent a disproportionation reaction. **Conclusion**: Ca(OCl)₂ does not undergo disproportionation. ### Final Answer: The species that does not disproportionate in water at room temperature is **Ca(OCl)₂**. ---

To determine which of the given ionic/molecular species does not disproportionate in water at room temperature, we will analyze each species one by one. ### Step-by-Step Solution: 1. **Identify the Species**: The species given are: - NO2 (Nitrogen dioxide) - Cu⁺ (Copper(I) ion) - MnO4²⁻ (Manganate ion) ...
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VK JAISWAL ENGLISH-TYPES OF REACTIONS-LEVEL 2
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  3. Which of the following ionic/molecular species does not disproportiona...

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  5. Which of the following combination does not evolve Cl(2) gas?

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  6. Which of the following combination does not liberated NH(3) gas?

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  7. Which of the following compound on heating does not produce metal oxid...

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  8. Select the compound in which HCl is not the product of Hydrolysis:

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  10. Consider the following sequence of reaction: M^(2+)(aq.) overset(NH(...

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  11. Which of the following compound does not liberated oxygen gas on warmi...

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  14. Pb+dil." "HNO(3) overset(warm)to P+Quarr+H(2)O incorrect statement f...

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  15. In which of the following redox reaction precipitate is not formed?

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  16. Which metal sulphide is soluble in excess NH(3) solution?

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  17. I^(-)(aq.)+MnO(4)^(-)(aq.)overset(H^(+))toX+Mn^(2+)(aq.) I^(-)(aq.)+...

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  19. (P)overset(Delta)to(Q)Metallic solid +(R)uarr+(S)uarr (X)overset(Del...

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