`I^(-)(aq.)+MnO_(4)^(-)(aq.)overset(H^(+))toX+Mn^(2+)(aq.)`
`I^(-)(aq.)+MnO_(4)^(-)(aq.) underset("weakly "OH^(-))overset("Neutral or")to Y+MnO_(2)`
`MnO_(4)^(-)(aq.)+Mn^(2+)(aq.) overset(ZnSO_(4)) to Z+4H^(+)`
Product X, Y and Z are respectively.

Options

A. `I_(2),IO_(3)^(-),MnO_(2)`
B. `IO_(3)^(-),I_(2),MnO_(2)`
C. `I_(2),IO_(3)^(-),MnO_(4)^(2-)`
D. `IO_(3)^(-),I_(2),MnO_(4)^(2-)`

Explanation

To solve the given reactions step by step, we will analyze each reaction separately to determine the products X, Y, and Z.

### Step 1: Analyze the first reaction
**Reaction:**
\[ I^{-} (aq) + MnO_{4}^{-} (aq) \overset{H^{+}}{\rightarrow} X + Mn^{2+} (aq) \]

- **Oxidation and Reduction:**
- The iodide ion \( I^{-} \) is oxidized to iodine \( I_{2} \) (oxidation state changes from -1 to 0).
- The permanganate ion \( MnO_{4}^{-} \) is reduced to \( Mn^{2+} \) (oxidation state changes from +7 to +2).

- **Product X:**
Therefore, the product X is \( I_{2} \).

### Step 2: Analyze the second reaction
**Reaction:**
\[ I^{-} (aq) + MnO_{4}^{-} (aq) \underset{\text{weakly } OH^{-}}{\rightarrow} Y + MnO_{2} \]

- **Oxidation and Reduction:**
- In a neutral or weakly basic medium, the iodide ion \( I^{-} \) is oxidized to iodate \( IO_{3}^{-} \) (oxidation state changes from -1 to +5).
- The permanganate ion \( MnO_{4}^{-} \) is reduced to manganese dioxide \( MnO_{2} \) (oxidation state changes from +7 to +4).

- **Product Y:**
Therefore, the product Y is \( IO_{3}^{-} \).

### Step 3: Analyze the third reaction
**Reaction:**
\[ MnO_{4}^{-} (aq) + Mn^{2+} (aq) \overset{ZnSO_{4}}{\rightarrow} Z + 4H^{+} \]

- **Comproportionation Reaction:**
- In this reaction, \( MnO_{4}^{-} \) (oxidation state +7) and \( Mn^{2+} \) (oxidation state +2) undergo a comproportionation reaction to form \( MnO_{2} \) (oxidation state +4).
- The by-product of this reaction is \( 4H^{+} \).

- **Product Z:**
Therefore, the product Z is \( MnO_{2} \).

### Final Products
- **Product X:** \( I_{2} \)
- **Product Y:** \( IO_{3}^{-} \)
- **Product Z:** \( MnO_{2} \)

### Summary of Products
- X = \( I_{2} \)
- Y = \( IO_{3}^{-} \)
- Z = \( MnO_{2} \)

---