What are formed products, when aqueous solution of `CuCl_(2)` and `(NH_(4))_(2)`S are mixed?

Options

A. CuS(aq.) and `NH_(4)Cl(s)`
B. `CuS(s) and NH_(4)Cl(aq.)`
C. `CuS(aq.) and NH_(4)Cl(g)`
D. `CuS(s) and NH_(4)Cl(s)`

Explanation

To determine the products formed when an aqueous solution of \( \text{CuCl}_2 \) (copper(II) chloride) is mixed with \( (NH_4)_2S \) (ammonium sulfide), we can follow these steps:

### Step 1: Write the Reactants
The reactants in this reaction are:
- Copper(II) chloride: \( \text{CuCl}_2 \) (aqueous)
- Ammonium sulfide: \( (NH_4)_2S \) (aqueous)

### Step 2: Identify the Reaction
When these two solutions are mixed, a double displacement reaction occurs. In this type of reaction, the cations and anions exchange partners.

### Step 3: Predict the Products
The possible products from the reaction of \( \text{CuCl}_2 \) and \( (NH_4)_2S \) are:
- Copper(II) sulfide: \( \text{CuS} \) (which is insoluble in water and will precipitate out as a solid)
- Ammonium chloride: \( \text{NH}_4\text{Cl} \) (which is soluble in water and will remain in solution)

### Step 4: Write the Balanced Chemical Equation
The balanced chemical equation for the reaction is:
\[ \text{CuCl}_2 (aq) + (NH_4)_2S (aq) \rightarrow \text{CuS} (s) + 2 \text{NH}_4\text{Cl} (aq) \]

### Step 5: Identify the Physical States of the Products
From the reaction:
- \( \text{CuS} \) is a solid (s)
- \( \text{NH}_4\text{Cl} \) is aqueous (aq)

### Conclusion
The products formed when an aqueous solution of \( \text{CuCl}_2 \) and \( (NH_4)_2S \) are mixed are:
- Copper(II) sulfide \( \text{CuS} \) (solid)
- Ammonium chloride \( \text{NH}_4\text{Cl} \) (aqueous)