`NH_(3)` gas does not liberate by which of the following combination?

Options

A. Heating of `NH_(4)ClO_(4)`
B. Heating of `NH_(4)Cl`
C. `(NH_(4))_(2)CO_(3)+NaOH`
D. `Li_(3)N+H_(2)O`

Explanation

To determine which combination does not liberate NH3 gas, we can analyze the reactions of the given compounds step by step.

### Step-by-Step Solution:

1. **Identify the Compounds**: The question asks about the liberation of NH3 gas from various combinations. The key compound we will focus on is NH4ClO4.

2. **Analyze the Reaction of NH4ClO4**:
- When NH4ClO4 is heated, it undergoes decomposition.
- The reaction can be written as:
\[ 2 \, \text{NH}_4\text{ClO}_4 \rightarrow \text{N}_2 + \text{Cl}_2 + 2 \, \text{O}_2 + 4 \, \text{H}_2\text{O} \]
- In this reaction, nitrogen gas (N2) is produced instead of ammonia (NH3).

3. **Check Other Reactions**:
- **Heating NH4Cl**:
\[ \text{NH}_4\text{Cl} \rightarrow \text{NH}_3 + \text{HCl} \]
- This reaction produces NH3.
- **Li3N with H2O**:
\[ \text{Li}_3\text{N} + 3 \, \text{H}_2\text{O} \rightarrow 3 \, \text{LiOH} + \text{NH}_3 \]
- This reaction also produces NH3.
- **NH4CO3 with NaOH**:
\[ \text{NH}_4\text{CO}_3 + \text{NaOH} \rightarrow \text{Na}_2\text{CO}_3 + 2 \, \text{NH}_3 + 2 \, \text{H}_2\text{O} \]
- This reaction produces NH3 as well.

4. **Conclusion**: The only combination that does not liberate NH3 gas is the heating of NH4ClO4, which produces N2 instead.

### Final Answer:
The combination that does not liberate NH3 gas is **option A: heating of NH4ClO4**.