Which of the following radical does not liberate gas with (Zn+dil. HCl) on warming?

Options

A. `S^(2-)`
B. `SO_(3)^(2-)`
C. `NO_(3)^(2-)`
D. `CH_(3)COO^(-)`

Explanation

To solve the question "Which of the following radical does not liberate gas with (Zn + dil. HCl) on warming?", we will analyze each radical provided in the options.

### Step-by-Step Solution:

1. **Identify the Radicals**: The given radicals are:
- S²⁻ (sulfide ion)
- SO₃²⁻ (sulfite ion)
- NO₃⁻ (nitrate ion)
- CH₃CO⁻ (acetate ion)

2. **Reaction with Zinc and Dilute HCl**: We need to determine how each radical reacts when treated with zinc and dilute hydrochloric acid (HCl).

3. **Sulfide Ion (S²⁻)**:
- When S²⁻ is treated with Zn and dilute HCl, it reduces to hydrogen sulfide (H₂S) gas.
- **Gas Released**: Yes (H₂S).

4. **Sulfite Ion (SO₃²⁻)**:
- When SO₃²⁻ reacts with Zn and dilute HCl, it also reduces to hydrogen sulfide (H₂S) gas.
- **Gas Released**: Yes (H₂S).

5. **Nitrate Ion (NO₃⁻)**:
- When NO₃⁻ is treated with Zn and dilute HCl, it is first reduced to ammonia (NH₃) gas. However, NH₃ immediately reacts with HCl to form ammonium chloride (NH₄Cl), which is a solid.
- **Gas Released**: No (the final product is solid).

6. **Acetate Ion (CH₃CO⁻)**:
- When CH₃CO⁻ reacts with Zn and dilute HCl, it undergoes reduction to form ethane (C₂H₆) gas.
- **Gas Released**: Yes (C₂H₆).

7. **Conclusion**: Among the radicals, the only one that does not liberate gas when treated with Zn and dilute HCl is the nitrate ion (NO₃⁻).

### Final Answer:
The radical that does not liberate gas with (Zn + dil. HCl) on warming is **NO₃⁻ (nitrate ion)**.

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