`SO_(2)(g)+Cl_(2)(g) to X overset(P_(4)) to Y+Z`
then X, Y and Z can be :

Options

A. `SOCl_(2)`
B. `SO_(2)Cl_(2)`
C. `SO_2`
D. `PC l_(5)`

Explanation

To solve the problem step by step, we will analyze the given reaction and identify the products formed at each stage.

### Step 1: Identify the first reaction
We start with the reaction:
\[ \text{SO}_2(g) + \text{Cl}_2(g) \rightarrow X \]

When sulfur dioxide (SO₂) reacts with chlorine gas (Cl₂), they form a compound. The expected product of this reaction is:
\[ \text{SO}_2Cl_2 \]
Thus, we can identify:
\[ X = \text{SO}_2Cl_2 \]

### Step 2: Identify the second reaction
Next, we need to consider the reaction of \( X \) with \( P_4 \):
\[ X + P_4 \rightarrow Y + Z \]

Substituting \( X \) with \( \text{SO}_2Cl_2 \):
\[ \text{SO}_2Cl_2 + P_4 \rightarrow Y + Z \]

In this reaction, phosphorus (P₄) reacts with sulfur dichloride (SO₂Cl₂) to produce phosphorus pentachloride (PCl₅) and sulfur dioxide (SO₂). Therefore, we can identify:
\[ Y = \text{PCl}_5 \]
\[ Z = \text{SO}_2 \]

### Conclusion
From the analysis, we conclude:
- \( X = \text{SO}_2Cl_2 \)
- \( Y = \text{PCl}_5 \)
- \( Z = \text{SO}_2 \)

Thus, the final answer is:
- \( X \) is \( \text{SO}_2Cl_2 \)
- \( Y \) is \( \text{PCl}_5 \)
- \( Z \) is \( \text{SO}_2 \)