Which of the following compound(s) give two acids on dissolution in `H_(2)O`?

Options

A. `P_(4)O_(8)`
B. `PCl_(3)`
C. `NO_(2)`
D. `C_(3)O_(2)`

Explanation

To determine which compounds give two acids upon dissolution in water, let's analyze each compound step by step:

### Step 1: Analyze P4O8
- **Reaction**: When P4O8 is dissolved in water (H2O), it reacts to form two acids:
- **Products**: H3PO3 (phosphorous acid) and H3PO4 (phosphoric acid).
- **Conclusion**: P4O8 produces two acids.

### Step 2: Analyze PCl3
- **Reaction**: When PCl3 is dissolved in water, it reacts to form:
- **Products**: H3PO4 (phosphoric acid) and HCl (hydrochloric acid).
- **Conclusion**: PCl3 also produces two acids.

### Step 3: Analyze NO2
- **Reaction**: When NO2 is dissolved in water, it reacts to form:
- **Products**: HNO3 (nitric acid) and HNO2 (nitrous acid).
- **Conclusion**: NO2 produces two acids as well.

### Step 4: Analyze C2O3
- **Reaction**: When C2O3 is dissolved in water, it reacts to form:
- **Products**: Malonic acid (HOOC-CH2-COOH).
- **Conclusion**: C2O3 produces only one acid.

### Final Conclusion
Based on the analysis:
- **Compounds that give two acids**: P4O8, PCl3, and NO2.
- **Compound that gives only one acid**: C2O3.

Thus, the answer is that the compounds P4O8, PCl3, and NO2 give two acids upon dissolution in water.