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Find out number ionic compound(s0 which is/are water insoluble at room temperature
`BaSO_(4)," "AgNO_(3)," "PbCO_(3)," "CaCl_(2)," "Mg(OH)_(2)," "KMnO_(4)," "CH_(3)COOAg," "Ca_(3)(PO_(4))_(2)," "(NH_(4))_(2)S`

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To determine the number of ionic compounds that are water insoluble at room temperature from the given list, we will analyze each compound one by one based on their solubility rules. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds given are: - BaSO₄ - AgNO₃ - PbCO₃ - CaCl₂ - Mg(OH)₂ - KMnO₄ - CH₃COOAg - Ca₃(PO₄)₂ - (NH₄)₂S 2. **Analyze Each Compound for Solubility**: - **BaSO₄ (Barium Sulfate)**: Insoluble in water. (1) - **AgNO₃ (Silver Nitrate)**: Soluble in water. (0) - **PbCO₃ (Lead Carbonate)**: Insoluble in water. (2) - **CaCl₂ (Calcium Chloride)**: Soluble in water. (0) - **Mg(OH)₂ (Magnesium Hydroxide)**: Insoluble in water. (3) - **KMnO₄ (Potassium Permanganate)**: Soluble in water. (0) - **CH₃COOAg (Silver Acetate)**: Insoluble in water. (4) - **Ca₃(PO₄)₂ (Calcium Phosphate)**: Insoluble in water. (5) - **(NH₄)₂S (Ammonium Sulfide)**: Soluble in water. (0) 3. **Count the Insoluble Compounds**: From the analysis: - BaSO₄: Insoluble (1) - PbCO₃: Insoluble (2) - Mg(OH)₂: Insoluble (3) - CH₃COOAg: Insoluble (4) - Ca₃(PO₄)₂: Insoluble (5) Total number of insoluble compounds = 5. ### Final Answer: The number of ionic compounds that are water insoluble at room temperature is **5**. ---

To determine the number of ionic compounds that are water insoluble at room temperature from the given list, we will analyze each compound one by one based on their solubility rules. ### Step-by-Step Solution: 1. **Identify the Compounds**: The compounds given are: - BaSO₄ - AgNO₃ ...
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Find the value of expression |x-y| for following compounds. where, x=total number of water insoluble salts. y=total number of salts, which can liberate non-olar acidic gas during their complete thermal decomposition. BaCO_(3)," "PbSO_(4)," "AgNO_(3)," "CaC_(2)O_(4)," "CsHCO_(3)," "Na_(3)PO_(4)," "CH_(3)COOAg," "Mg(OH)_(2)," "Pb(NO_(3))_(2)

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