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Calculate difference between oxidation state of chromium (Cr) in blue and green coloured chromium species formed during the following given transformation.

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To calculate the difference between the oxidation states of chromium (Cr) in the blue and green colored chromium species formed during the transformation, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Blue Colored Chromium Species**: - The blue colored chromium species is CrO5. 2. **Determine the Oxidation State of Chromium in CrO5**: - In CrO5, we need to find the oxidation state of chromium (let's denote it as x). - The formula for CrO5 consists of 4 oxygen atoms with a -1 oxidation state (peroxide) and 1 oxygen atom with a -2 oxidation state. - Therefore, the equation can be set up as: \[ x + 4(-1) + (-2) = 0 \] - Simplifying this gives: \[ x - 4 - 2 = 0 \implies x = +6 \] - Thus, the oxidation state of chromium in CrO5 is +6. 3. **Identify the Green Colored Chromium Species**: - The green colored chromium species is Cr3+. 4. **Determine the Oxidation State of Chromium in Cr3+**: - The oxidation state of chromium in Cr3+ is simply +3. 5. **Calculate the Difference in Oxidation States**: - Now, we find the difference between the oxidation states of chromium in CrO5 and Cr3+: \[ \text{Difference} = \text{Oxidation state in CrO5} - \text{Oxidation state in Cr3+} = +6 - (+3) = +3 \] ### Final Answer: The difference between the oxidation state of chromium in blue colored CrO5 and green colored Cr3+ is **3**. ---
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