If hydrolysis of interhalogen compound can be represented by following general reaction:
`XY_(n_(1))overset(water)to n_(1)HY+HXO_(n_(2))`
If given interhalogen compound is polarr and non-planar, then calculate value of `n_(1)+n_(2)`.

Explanation

To solve the problem, we need to analyze the hydrolysis of the interhalogen compound represented by the equation:

\[ XY_{n_1} + \text{water} \rightarrow n_1 HY + HXO_{n_2} \]

1. **Identify the Interhalogen Compound**:
- The interhalogen compound is denoted as \( XY_{n_1} \). Given that it is polar and non-planar, we can infer that it is likely a compound like \( XY_5 \) (for example, \( ClF_5 \) or \( BrF_5 \)).

2. **Determine the Value of \( n_1 \)**:
- For the interhalogen compound \( XY_5 \), we have \( n_1 = 5 \). This means there are 5 halogen atoms bonded to the central atom.

3. **Write the Hydrolysis Reaction**:
- The hydrolysis reaction can be represented as:
\[ XY_5 + 5 \text{H}_2O \rightarrow 5 HY + HXO_{n_2} \]

4. **Determine the Value of \( n_2 \)**:
- In the hydrolysis of \( XY_5 \), we produce \( 5 HY \) and \( HXO_{n_2} \). The product \( HXO_{n_2} \) typically corresponds to a species like \( HXO_3 \) (for example, \( HClO_3 \) or \( HBrO_3 \)).
- In this case, we find that \( n_2 = 3 \) since \( HXO_3 \) has 3 oxygen atoms.

5. **Calculate \( n_1 + n_2 \)**:
- Now, we can calculate the total:
\[ n_1 + n_2 = 5 + 3 = 8 \]

Thus, the final answer is:
\[ n_1 + n_2 = 8 \]

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